What is the integral of arctan(1) ?

The integral of arctan(1) is pi/4 x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of arctan(1)

\int arctan (1) d x

\frac{π}{4} x + C

Solution steps

\int arctan (1) d x

Integral of a constant:

\int a d x = a x

= arctan (1) x

Use the following trivial identity:

arctan (1) = \frac{π}{4}

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{4} x

Add a constant to the solution

= \frac{π}{4} x + C

x \to 0 lim (x (e^{x} + \frac{1}{x}))

(2 cos (t))^{^{'}}

\frac{16 x}{x ^{2} + 16}

\int - 12 cos (ln (x)) d x

\frac{\partial}{\partial t} (1 + (t - y)^{2})