What is the integral from 2 to 3 of 3x^2 ?

The integral from 2 to 3 of 3x^2 is 19

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integral from 2 to 3 of 3x^2

\int_{2}^{3} 3 x^{2} d x

19

Solution steps

\int_{2}^{3} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{2}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{2}^{3}

= 3 [\frac{x ^{3}}{3}]_{2}^{3}

Compute the boundaries:

\frac{19}{3}

= 3 \cdot \frac{19}{3}

Simplify

= 19

2 x + 3

\frac{d}{d x} ((1 + 1 0^{l n (x)})^{6})

\int \frac{1}{3 - 2 x - x ^{2}} d x

\frac{d}{d x} (\frac{x ^{3} + x + 2}{x - 1})

\frac{\partial}{\partial x} (\frac{7 x y ^{2}}{x ^{2} + y ^{4}})

What is the integral from 2 to 3 of 3x^2 ?
The integral from 2 to 3 of 3x^2 is 19