What is the derivative of (x(2-x)/(e^x)) ?

The derivative of (x(2-x)/(e^x)) is (2-4x+x^2)/(e^x)

What is the first derivative of (x(2-x)/(e^x)) ?

The first derivative of (x(2-x)/(e^x)) is (2-4x+x^2)/(e^x)

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\frac{d}{d x} (\frac{x ( 2 - x )}{e ^{x}})

\frac{2 - 4 x + x ^{2}}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{x ( 2 - x )}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ( 2 - x ) ) e ^{x} - \frac{d}{d x} ( e ^{x} ) x ( 2 - x )}{( e ^{x} ) ^{2}}

\frac{d}{d x} (x (2 - x)) = 2 - 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{( 2 - 2 x ) e ^{x} - e ^{x} x ( 2 - x )}{( e ^{x} ) ^{2}}

Simplify

\frac{( 2 - 2 x ) e ^{x} - e ^{x} x ( 2 - x )}{( e ^{x} ) ^{2}} : \frac{2 - 4 x + x ^{2}}{e ^{x}}

= \frac{2 - 4 x + x ^{2}}{e ^{x}}

\int (\frac{1}{ln ( x )}) d x

\int x^{2} (x - 5) 7 - x d x

\frac{d}{d w} (t e^{(\frac{w}{t})})

(\frac{1}{x + 1})^{^{'}}

\int (2 x - cos (6 x)) d x

What is the derivative of (x(2-x)/(e^x)) ?
The derivative of (x(2-x)/(e^x)) is (2-4x+x^2)/(e^x)
What is the first derivative of (x(2-x)/(e^x)) ?
The first derivative of (x(2-x)/(e^x)) is (2-4x+x^2)/(e^x)