What is the solution for (dP)/(dt)=P-P^2 ?

The solution for (dP)/(dt)=P-P^2 is P=-(e^{t+c_{1}})/(1-e^{t+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dP)/(dt)=P-P^2

\frac{d P}{d t} = P - P^{2}

P = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

Solution steps

\frac{d P}{d t} = P - P^{2}

Solve separable ODE:

P = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

P = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

(2) (e^{3 x})

\frac{d y}{d x}, x^{2} + x y + y^{2} = 7

\int_{0}^{\frac{π}{3}} 2 sec^{2} (x) d x

f (x) = x + 3, g (x) = \frac{1}{2} x + 3

\int_{0}^{5} \frac{1}{( 5 - x ) ^{\frac{1}{3}}} d x

What is the solution for (dP)/(dt)=P-P^2 ?
The solution for (dP)/(dt)=P-P^2 is P=-(e^{t+c_{1}})/(1-e^{t+c_{1)}}