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Popular >

t^2y^'+ty=t^5

Solution

t^{2} y^{^{'}} + t y = t^{5}

Solution

y = \frac{t ^{4}}{5} + \frac{c _{1}}{t}

Solution steps

t^{2} y^{'} (t) + t y = t^{5}

Solve linear ODE:

y = \frac{t ^{4}}{5} + \frac{c _{1}}{t}

y = \frac{t ^{4}}{5} + \frac{c _{1}}{t}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for t^2y^'+ty=t^5 ?
The solution for t^2y^'+ty=t^5 is y=(t^4)/5+(c_{1})/t