What is (\partial)/(\partial y)(2sqrt(y)) ?

The answer to (\partial)/(\partial y)(2sqrt(y)) is 1/(sqrt(y))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2sqrt(y))

\frac{\partial}{\partial y} (2 y)

\frac{1}{y}

Solution steps

\frac{\partial}{\partial y} (2 y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial y} (y)

Apply radical rule:

a = a^{\frac{1}{2}}

= 2 \frac{\partial}{\partial y} (y^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot \frac{1}{2} y^{\frac{1}{2} - 1}

Simplify

2 \cdot \frac{1}{2} y^{\frac{1}{2} - 1} : \frac{1}{y}

= \frac{1}{y}

\int \frac{3}{x 4 - x ^{2}} d x

(- 2, 1), (1, 6)

\frac{d}{d x} (e^{(3 - 2 x)})

\frac{d}{d u} (u^{- 1})

\frac{d}{d x} (\frac{x ^{2} + 3}{2})

What is (\partial)/(\partial y)(2sqrt(y)) ?
The answer to (\partial)/(\partial y)(2sqrt(y)) is 1/(sqrt(y))