What is the derivative of y=x^2+2x-3 ?

The derivative of y=x^2+2x-3 is 2x+2

What is the first derivative of y=x^2+2x-3 ?

The first derivative of y=x^2+2x-3 is 2x+2

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derivative of

y = x^{2} + 2 x - 3

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

\frac{6}{x}

y = e^{s} (s^{3} + 5), (0, 5)

\int \frac{e ^{6 x}}{e ^{2 x}} d x

\frac{\partial}{\partial x} (2 x + y^{10})

\int (π^{2} - 1) d x

What is the derivative of y=x^2+2x-3 ?
The derivative of y=x^2+2x-3 is 2x+2
What is the first derivative of y=x^2+2x-3 ?
The first derivative of y=x^2+2x-3 is 2x+2