What is the derivative of 3x^{k-2}+2kx^{k-1}+4x^k ?

The derivative of 3x^{k-2}+2kx^{k-1}+4x^k is 3x^{k-3}(k-2)+2kx^{k-2}(k-1)+4kx^{k-1}

What is the first derivative of 3x^{k-2}+2kx^{k-1}+4x^k ?

The first derivative of 3x^{k-2}+2kx^{k-1}+4x^k is 3x^{k-3}(k-2)+2kx^{k-2}(k-1)+4kx^{k-1}

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\frac{d}{d x} (3 x^{k - 2} + 2 k x^{k - 1} + 4 x^{k})

3 x^{k - 3} (k - 2) + 2 k x^{k - 2} (k - 1) + 4 k x^{k - 1}

Solution steps

\frac{d}{d x} (3 x^{k - 2} + 2 k x^{k - 1} + 4 x^{k})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{k - 2}) + \frac{d}{d x} (2 k x^{k - 1}) + \frac{d}{d x} (4 x^{k})

\frac{d}{d x} (3 x^{k - 2}) = 3 x^{k - 3} (k - 2)

\frac{d}{d x} (2 k x^{k - 1}) = 2 k x^{k - 2} (k - 1)

\frac{d}{d x} (4 x^{k}) = 4 k x^{k - 1}

= 3 x^{k - 3} (k - 2) + 2 k x^{k - 2} (k - 1) + 4 k x^{k - 1}

\int \frac{x}{( x - 2 ) ^{3}} d x

\frac{d}{d x} (\frac{1}{4} e^{x} + \frac{3}{4} e^{- x})

\frac{d}{d x} (5 ln (x) - \frac{x ^{2}}{40})

\frac{d}{d x} (\frac{1 + x ^{2}}{x})

x \to 4 lim (\frac{6}{x})

What is the derivative of 3x^{k-2}+2kx^{k-1}+4x^k ?
The derivative of 3x^{k-2}+2kx^{k-1}+4x^k is 3x^{k-3}(k-2)+2kx^{k-2}(k-1)+4kx^{k-1}
What is the first derivative of 3x^{k-2}+2kx^{k-1}+4x^k ?
The first derivative of 3x^{k-2}+2kx^{k-1}+4x^k is 3x^{k-3}(k-2)+2kx^{k-2}(k-1)+4kx^{k-1}