What is the solution for (dy)/(dt)=5*(y-t^2) ?

The solution for (dy)/(dt)=5*(y-t^2) is y=t^2+(2t)/5+2/25+c_{1}e^{5t}

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(dy)/(dt)=5*(y-t^2)

\frac{d y}{d t} = 5 \cdot (y - t^{2})

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

Solution steps

\frac{d y}{d t} = 5 \cdot (y - t^{2})

Solve linear ODE:

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

y = t^{2} + \frac{2 t}{5} + \frac{2}{25} + c_{1} e^{5 t}

\frac{\partial}{\partial x} (\frac{1}{( 1 - x ) ^{2}})

sin (\frac{t}{2})

\frac{d}{d x} (cos (\frac{x + 1}{x - 1}))

\frac{d}{d x} (x in x)

\int \frac{1}{3 + 2 x} d x

What is the solution for (dy)/(dt)=5*(y-t^2) ?
The solution for (dy)/(dt)=5*(y-t^2) is y=t^2+(2t)/5+2/25+c_{1}e^{5t}