What is the tangent of y= 1/(x^4),(3, 1/81) ?

The tangent of y= 1/(x^4),(3, 1/81) is y=-4/243 x+5/81

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tangent of y= 1/(x^4),(3, 1/81)

tangent of

y = \frac{1}{x ^{4}}, (3, \frac{1}{81})

y = - \frac{4}{243} x + \frac{5}{81}

Solution steps

Find the slope of

y = \frac{1}{x ^{4}} : \frac{d y}{d x} = - \frac{4}{x ^{5}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{4}{243}

Find the line with slope m=

- \frac{4}{243}

and passing through

(3, \frac{1}{81}) : y = - \frac{4}{243} x + \frac{5}{81}

y = - \frac{4}{243} x + \frac{5}{81}

x ∣ x ∣

\int \frac{1}{sin ^{2} ( x )} d x

x \to 2 + lim (\frac{x + 1}{x - 2})

\int_{0}^{π} 5 sin^{2} (t co) s^{4} t d t

f (x) = (ln (x))^{4}, at x = 2

What is the tangent of y= 1/(x^4),(3, 1/81) ?
The tangent of y= 1/(x^4),(3, 1/81) is y=-4/243 x+5/81