What is (\partial)/(\partial u)(vcos(u)) ?

The answer to (\partial)/(\partial u)(vcos(u)) is -vsin(u)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial u)(vcos(u))

\frac{\partial}{\partial u} (v cos (u))

- v sin (u)

Solution steps

\frac{\partial}{\partial u} (v cos (u))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= v \frac{\partial}{\partial u} (cos (u))

Apply the common derivative:

\frac{\partial}{\partial u} (cos (u)) = - sin (u)

= v (- sin (u))

Simplify

= - v sin (u)

\frac{d ^{2}}{d x ^{2}} (sin^{2} (x))

\frac{d}{d x} (\frac{4}{x ^{4}} - 5 3 x)

\int \frac{5}{x ^{2} + 4} d x

\int \frac{2 x ^{3} - 2 x ^{2} + 1}{x ^{2} - x} d x

x \to \infty lim (\frac{3 ^{x - 3}}{2 ^{n + 3}})

What is (\partial)/(\partial u)(vcos(u)) ?
The answer to (\partial)/(\partial u)(vcos(u)) is -vsin(u)