What is area y=x^{-3},1<= x<= 6 ?

The answer to area y=x^{-3},1<= x<= 6 is 35/72

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area y=x^{-3},1<= x<= 6

area

y = x^{- 3}, 1 \leq x \leq 6

\frac{35}{72}

Decimal

0.48611 \dots

Solution steps

Apply the area formula:

\int_{1}^{6} \frac{1}{∣ x ^{3} ∣} d x

Solve

\int_{1}^{6} \frac{1}{∣ x ^{3} ∣} d x : \frac{35}{72}

The area is:

= \frac{35}{72}

\int_{- 2}^{2} x^{2} - 2 d x

\int ln (3 - x) d x

\int_{1}^{2} \frac{x - 1}{2 x} d x

\frac{\partial}{\partial y} (sin (\frac{5 x}{y}))

y = \frac{4}{x}, y = x, y = 4

What is area y=x^{-3},1<= x<= 6 ?
The answer to area y=x^{-3},1<= x<= 6 is 35/72