What is the tangent of f(x)=9e^x+x,(0,9) ?

The tangent of f(x)=9e^x+x,(0,9) is y=10x+9

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tangent of f(x)=9e^x+x,(0,9)

tangent of

f (x) = 9 e^{x} + x, (0, 9)

y = 10 x + 9

Solution steps

Find the slope of

f (x) = 9 e^{x} + x : \frac{df ( x )}{d x} = 9 e^{x} + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 10

Find the line with slope m=

10

and passing through

(0, 9) : y = 10 x + 9

y = 10 x + 9

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x \to 0 lim (6 cos (6 x))

What is the tangent of f(x)=9e^x+x,(0,9) ?
The tangent of f(x)=9e^x+x,(0,9) is y=10x+9