What is the integral of (3x)/(sqrt(3-x^2)) ?

The integral of (3x)/(sqrt(3-x^2)) is -3sqrt(3-x^2)+C

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integral of (3x)/(sqrt(3-x^2))

\int \frac{3 x}{3 - x ^{2}} d x

- 3 3 - x^{2} + C

Solution steps

\int \frac{3 x}{3 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x}{3 - x ^{2}} d x

Apply u-substitution

: \int - \frac{1}{2 u} d u

= 3 \cdot \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- \frac{1}{2} \cdot \int \frac{1}{u} d u)

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 3 (- \frac{1}{2} \cdot 2 u^{\frac{1}{2}})

Substitute back

u = 3 - x^{2}

= 3 (- \frac{1}{2} \cdot 2 (3 - x^{2})^{\frac{1}{2}})

Simplify

3 (- \frac{1}{2} \cdot 2 (3 - x^{2})^{\frac{1}{2}}) : - 3 3 - x^{2}

= - 3 3 - x^{2}

Add a constant to the solution

= - 3 3 - x^{2} + C

f (x) = - 5 x + 2

\frac{d y}{d x} + 4 y = 8

\int \frac{9}{x ^{3} - 3 x ^{2}} d x

y^{^{'}} + 5 y = cos (x)

\int 3 x sec^{2} (4 x^{2}) d x

What is the integral of (3x)/(sqrt(3-x^2)) ?
The integral of (3x)/(sqrt(3-x^2)) is -3sqrt(3-x^2)+C