What is the limit as x approaches 0 of ((e^x-1))/x ?

The limit as x approaches 0 of ((e^x-1))/x is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ((e^x-1))/x

x \to 0 lim (\frac{( e ^{x} - 1 )}{x})

1

Solution steps

x \to 0 lim (\frac{e ^{x} - 1}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{e ^{x}}{1})

= x \to 0 lim (\frac{e ^{x}}{1})

Plug in the value

x = 0

= \frac{e ^{0}}{1}

Simplify

= 1

\int (4 x^{3} - 3 x^{2} + 6 x - 1) d x

x \to 0 lim (sin (x) ln (2 x))

\frac{1}{1 + u ^{2}} d u = d x

\frac{d}{d x} (\frac{7 x}{6})

\frac{\partial}{\partial x} (6 e^{x^{5} y^{3}})

What is the limit as x approaches 0 of ((e^x-1))/x ?
The limit as x approaches 0 of ((e^x-1))/x is 1