What is the slope of f(x)=x^4-17x^2+16 ?

The slope of f(x)=x^4-17x^2+16 is 4x^3-34x

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slope of f(x)=x^4-17x^2+16

slope

f (x) = x^{4} - 17 x^{2} + 16

4 x^{3} - 34 x

Solution steps

f (x) = x^{4} - 17 x^{2} + 16

In order to find the slope of the function, take the derivative of

x^{4} - 17 x^{2} + 16

\frac{d}{d x} (x^{4} - 17 x^{2} + 16) = 4 x^{3} - 34 x

4 x^{3} - 34 x

\int_{0}^{1} x^{2} - x^{3} d x

f (x) = 2 x^{2} + 1, (- 1, 3)

f (x) = \frac{e ^{x}}{9 x ^{2} + 2}

\int \frac{1}{u ^{2}} d u

\int 4 e^{- 3 x} d x

What is the slope of f(x)=x^4-17x^2+16 ?
The slope of f(x)=x^4-17x^2+16 is 4x^3-34x