What is the derivative of sin(θ)+cos(θ) ?

The derivative of sin(θ)+cos(θ) is cos(θ)-sin(θ)

What is the first derivative of sin(θ)+cos(θ) ?

The first derivative of sin(θ)+cos(θ) is cos(θ)-sin(θ)

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derivative of

sin (θ) + cos (θ)

cos (θ) - sin (θ)

Solution steps

\frac{d}{d θ} (sin (θ) + cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (sin (θ)) + \frac{d}{d θ} (cos (θ))

\frac{d}{d θ} (sin (θ)) = cos (θ)

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= cos (θ) - sin (θ)

\frac{d}{d x} (2 sec (x) tan (x))

arctan (x), 0

\int \frac{e ^{c o s (x)}}{csc ( x )} d x

y y^{^{'}} = - t

y^{^{''}} + 2 y^{^{'}} + 17 y = 0, y (0) = 3, y^{^{'}} (0) = 0

What is the derivative of sin(θ)+cos(θ) ?
The derivative of sin(θ)+cos(θ) is cos(θ)-sin(θ)
What is the first derivative of sin(θ)+cos(θ) ?
The first derivative of sin(θ)+cos(θ) is cos(θ)-sin(θ)