What is the solution for (d^2y)/(dt^2)+9y=0 ?

The solution for (d^2y)/(dt^2)+9y=0 is y=c_{1}cos(3t)+c_{2}sin(3t)

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(d^2y)/(dt^2)+9y=0

\frac{d ^{2} y}{d t ^{2}} + 9 y = 0

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Solution steps

\frac{d ^{2} y}{d t ^{2}} + 9 y = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t)

\frac{d}{d x} (csc^{2} (x - 2))

\int_{0}^{1} x (1 - x)^{5} d x

\frac{\partial}{\partial x} (x^{0.4} y^{0.6})

\frac{d}{d x} (1 + 2 e^{3 x})

\int 16 cot^{4} (x) d x

What is the solution for (d^2y)/(dt^2)+9y=0 ?
The solution for (d^2y)/(dt^2)+9y=0 is y=c_{1}cos(3t)+c_{2}sin(3t)