What is (\partial}{\partial x}(\frac{y^4)/x) ?

The answer to (\partial}{\partial x}(\frac{y^4)/x) is -(y^4)/(x^2)

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(\partial}{\partial x}(\frac{y^4)/x)

\frac{\partial}{\partial x} (\frac{y ^{4}}{x})

- \frac{y ^{4}}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{y ^{4}}{x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= y^{4} \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{4} (- 1 \cdot x^{- 1 - 1})

Simplify

y^{4} (- 1 \cdot x^{- 1 - 1}) : - \frac{y ^{4}}{x ^{2}}

= - \frac{y ^{4}}{x ^{2}}

(2 t - 1) (3 t - 3)^{- 1}

\frac{d}{d x} (arcsin (x - y))

\int_{- 1}^{3} 3 x + 1 d x

y = x^{2}, at x = \frac{1}{3}

\frac{\partial}{\partial y} (\frac{5 ( y + 2 )}{( x + 2 ) ^{2}})

What is (\partial}{\partial x}(\frac{y^4)/x) ?
The answer to (\partial}{\partial x}(\frac{y^4)/x) is -(y^4)/(x^2)