What is the integral of x^3-2.5x+1 ?

The integral of x^3-2.5x+1 is 0.25x^4-1.25x^2+x+C

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integral of x^3-2.5x+1

\int x^{3} - 2.5 x + 1 d x

0.25 x^{4} - 1.25 x^{2} + x + C

Solution steps

\int x^{3} - 2.5 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 2.5 x d x + \int 1 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 2.5 x d x = 1.25 x^{2}

\int 1 d x = x

= \frac{x ^{4}}{4} - 1.25 x^{2} + x

Simplify

= 0.25 x^{4} - 1.25 x^{2} + x

Add a constant to the solution

= 0.25 x^{4} - 1.25 x^{2} + x + C

t \to 7 lim \frac{( t - 7 ) ^{3}}{t - 7}

\frac{\partial}{\partial x} ((2 x - 3 y)^{3})

n = 0 \sum \infty \frac{1}{10 n + 1}

\int (x^{3} - x) d x

n = 1 \sum \infty 3 (\frac{1}{2})^{n - 1}

What is the integral of x^3-2.5x+1 ?
The integral of x^3-2.5x+1 is 0.25x^4-1.25x^2+x+C