What is the derivative of e^{x+c} ?

The derivative of e^{x+c} is e^{x+c}

What is the first derivative of e^{x+c} ?

The first derivative of e^{x+c} is e^{x+c}

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\frac{d}{d x} (e^{x + c})

e^{x + c}

Solution steps

\frac{d}{d x} (e^{x + c})

Apply the chain rule:

e^{x + c} \frac{d}{d x} (x + c)

= e^{x + c} \frac{d}{d x} (x + c)

\frac{d}{d x} (x + c) = 1

= e^{x + c} \cdot 1

Simplify

= e^{x + c}

2 y^{^{''}} + 13 y^{^{'}} - 7 y = 0

\int \frac{1}{x ^{2} + t ^{2}} d x

\frac{d}{d x} (\frac{1}{3} tan^{3} (x) - tan (x) + x)

f (x) = (x + 9) (x^{2} - 9)

What is the derivative of e^{x+c} ?
The derivative of e^{x+c} is e^{x+c}
What is the first derivative of e^{x+c} ?
The first derivative of e^{x+c} is e^{x+c}