What is the integral from 0 to infinity of 1/(2x+5) ?

The integral from 0 to infinity of 1/(2x+5) is diverges

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integral from 0 to infinity of 1/(2x+5)

\int_{0}^{\infty} \frac{1}{2 x + 5} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{2 x + 5} d x

Compute the indefinite integral:

\int \frac{1}{2 x + 5} d x = \frac{1}{2} ln ∣ 2 x + 5 ∣ + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{2 x + 5} d x =

diverges

= diverges

\int_{0}^{1} \frac{1}{2 t ^{2} - 2 t + 1} d t

\frac{1}{1 - x ^{2}}, 0

\frac{d}{d x} (- \frac{x}{5})

x \to 2 lim (3 x^{3} - 5 x)

\int_{100}^{120} \frac{600}{x} d x

What is the integral from 0 to infinity of 1/(2x+5) ?
The integral from 0 to infinity of 1/(2x+5) is diverges