What is the derivative of-x^2+3x ?

The derivative of-x^2+3x is -2x+3

What is the first derivative of-x^2+3x ?

The first derivative of-x^2+3x is -2x+3

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\frac{d}{d x} (- x^{2} + 3 x)

- 2 x + 3

Solution steps

\frac{d}{d x} (- x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= - 2 x + 3

x \to \infty lim (\frac{1}{x ^{\frac{4}{3}}})

(x^{2} + 1) d y + (4 x y - x^{2}) d x = 0

\frac{d}{d y} (\frac{x}{y ^{2} + x ^{2}})

\int 4 x (2 x^{2} + 1) 8 d x

\frac{d y}{d t} - (\frac{3}{t}) \cdot y = 2 t^{3} \cdot e^{(2 t)}

What is the derivative of-x^2+3x ?
The derivative of-x^2+3x is -2x+3
What is the first derivative of-x^2+3x ?
The first derivative of-x^2+3x is -2x+3