What is the solution for (dy}{dx}=\frac{(x-1))/y ?

The solution for (dy}{dx}=\frac{(x-1))/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}

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(dy}{dx}=\frac{(x-1))/y

\frac{d y}{d x} = \frac{( x - 1 )}{y}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( x - 1 )}{y}

Solve separable ODE:

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

\frac{d}{d x} (7 arcsin (x^{2}))

y = 1 x, (0, 4)

t \frac{d y}{d t} + 9 y = \frac{1}{t}

\int \frac{2 y ^{2} - 3}{y ^{2}} d y

\frac{d}{d x} ((2 x)^{4 x})

What is the solution for (dy}{dx}=\frac{(x-1))/y ?
The solution for (dy}{dx}=\frac{(x-1))/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}