What is the derivative of 6\sqrt[3]{x} ?

The derivative of 6\sqrt[3]{x} is 2/(x^{2/3)}

What is the first derivative of 6\sqrt[3]{x} ?

The first derivative of 6\sqrt[3]{x} is 2/(x^{2/3)}

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derivative of

\frac{2}{x ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 6 \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 \cdot \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

6 \cdot \frac{1}{3} x^{\frac{1}{3} - 1} : \frac{2}{x ^{\frac{2}{3}}}

= \frac{2}{x ^{\frac{2}{3}}}

\frac{\partial}{\partial x} (2 x^{4} y + sin (x^{4}))

\int \frac{arcsin ( ln ( x ) )}{x} d x

\frac{1}{cos ( \frac{x}{2} )}

\frac{d}{d x} (- \frac{2 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}})

(x - 5) (x + 4) (x + 6)

What is the derivative of 6\sqrt[3]{x} ?
The derivative of 6\sqrt[3]{x} is 2/(x^{2/3)}
What is the first derivative of 6\sqrt[3]{x} ?
The first derivative of 6\sqrt[3]{x} is 2/(x^{2/3)}