What is (\partial)/(\partial y)(z-sqrt(x^2+y^2)) ?

The answer to (\partial)/(\partial y)(z-sqrt(x^2+y^2)) is -y/(sqrt(x^2+y^2))

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(\partial)/(\partial y)(z-sqrt(x^2+y^2))

\frac{\partial}{\partial y} (z - x^{2} + y^{2})

- \frac{y}{x ^{2} + y ^{2}}

Solution steps

\frac{\partial}{\partial y} (z - x^{2} + y^{2})

Treat

z, x

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (z) - \frac{\partial}{\partial y} (x^{2} + y^{2})

\frac{\partial}{\partial y} (z) = 0

\frac{\partial}{\partial y} (x^{2} + y^{2}) = \frac{y}{x ^{2} + y ^{2}}

= 0 - \frac{y}{x ^{2} + y ^{2}}

Simplify

= - \frac{y}{x ^{2} + y ^{2}}

\int 5 x^{2} + 3 d x

- 3 e^{x^{5}}

\frac{\partial}{\partial x} (\frac{5 y}{x ^{2} + y ^{2}})

\int \frac{( x - 1 )}{( x + 1 )} d x

\int e^{- t x} d x

What is (\partial)/(\partial y)(z-sqrt(x^2+y^2)) ?
The answer to (\partial)/(\partial y)(z-sqrt(x^2+y^2)) is -y/(sqrt(x^2+y^2))