What is area y=e^x,y=e^{2x},x=ln(2),x=ln(3) ?

The answer to area y=e^x,y=e^{2x},x=ln(2),x=ln(3) is 3/2

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area y=e^x,y=e^{2x},x=ln(2),x=ln(3)

area

y = e^{x}, y = e^{2 x}, x = ln (2), x = ln (3)

\frac{3}{2}

Decimal Notation

1.5

Solution steps

Apply the area formula:

\int_{l n (2)}^{l n (3)} e^{x} - e^{2 x} d x

Solve

\int_{l n (2)}^{l n (3)} e^{x} - e^{2 x} d x : \frac{3}{2}

The area is:

= \frac{3}{2}

x \to 0 + lim ((1 + 4 x)^{c o t (x)})

x^{2} + 1

y^{^{'}} = 2 y + 39

\frac{d}{d x} (\frac{x ^{\frac{3}{5}} x ^{3} + 2 x - 6}{( 4 x - 3 ) ^{8}})

f (x) = \frac{4}{x - 2}

What is area y=e^x,y=e^{2x},x=ln(2),x=ln(3) ?
The answer to area y=e^x,y=e^{2x},x=ln(2),x=ln(3) is 3/2