What is the sum from n=0 to infinity of (5^n)/(4^n) ?

The sum from n=0 to infinity of (5^n)/(4^n) is diverges

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sum from n=0 to infinity of (5^n)/(4^n)

n = 0 \sum \infty \frac{5 ^{n}}{4 ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{5 ^{n}}{4 ^{n}}

n \to \infty lim (n (\frac{\frac{5 ^{n}}{4 ^{n}}}{\frac{5 ^{n + 1}}{4 ^{n + 1}}} - 1)) = - \infty

L < 1,

by the Raabe's test

= diverges

\frac{d}{d x} (\frac{x ^{\frac{7}{3}} + 3 x ^{3} - 8}{6 x ^{2}})

x \to 0 lim (\frac{x + tan ( x )}{x})

\frac{d}{d x} (x^{v})

\int \frac{1 + x + x ^{2}}{x} d x

\int \frac{ln ( x )}{x ^{a}} d x

What is the sum from n=0 to infinity of (5^n)/(4^n) ?
The sum from n=0 to infinity of (5^n)/(4^n) is diverges