What is the tangent of cos(5+x^2) ?

The tangent of cos(5+x^2) is y=-sin(5+a_{0}^2)*2a_{0}x+cos(5+a_{0}^2)+2a_{0}^2sin(5+a_{0}^2)

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tangent of cos(5+x^2)

tangent of

cos (5 + x^{2})

y = - sin (5 + a_{0}^{2}) \cdot 2 a_{0} x + cos (5 + a_{0}^{2}) + 2 a_{0}^{2} sin (5 + a_{0}^{2})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, cos (5 + a_{0}^{2}))

Find the slope of

y = cos (5 + x^{2}) : \frac{d y}{d x} = - sin (5 + x^{2}) \cdot 2 x

Compute the slope of

y = cos (5 + x^{2})

x = a_{0} : m = - sin (5 + a_{0}^{2}) \cdot 2 a_{0}

Find the line with slope m=

- sin (5 + a_{0}^{2}) 2 a_{0}

and passing through

(a_{0}, cos (5 + a_{0}^{2})) : y = - sin (5 + a_{0}^{2}) \cdot 2 a_{0} x + cos (5 + a_{0}^{2}) + 2 a_{0}^{2} sin (5 + a_{0}^{2})

y = - sin (5 + a_{0}^{2}) \cdot 2 a_{0} x + cos (5 + a_{0}^{2}) + 2 a_{0}^{2} sin (5 + a_{0}^{2})

\frac{\partial}{\partial y} (- arctan (\frac{x}{y}))

\frac{3 ^{2}}{s ( s + 3 ) ^{2}}

\int (7 x^{2} + 4 x^{- 2}) d x

\int - 3 cot (x) d x

\frac{d}{d x} (cos (x) ln (tan (x)))

What is the tangent of cos(5+x^2) ?
The tangent of cos(5+x^2) is y=-sin(5+a_{0}^2)*2a_{0}x+cos(5+a_{0}^2)+2a_{0}^2sin(5+a_{0}^2)