What is the solution for (7y^2-t^2)/(y^5)(dy)/(dt)+t/(2y^4)=0 ?

The solution for (7y^2-t^2)/(y^5)(dy)/(dt)+t/(2y^4)=0 is

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(7y^2-t^2)/(y^5)(dy)/(dt)+t/(2y^4)=0

\frac{7 y ^{2} - t ^{2}}{y ^{5}} \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

y = \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}

Solution steps

\frac{7 y ^{2} - t ^{2}}{y ^{5}} \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

Solve exact ODE:

y = \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}

y = \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}

x \to 1 lim (\frac{4}{x + 3})

y^{^{'}} = 8 y^{2} sin (x)

t^{2} (t + 1)^{- 1}

3 x^{\frac{1}{3}}

y^{^{''}} + 2 y^{^{'}} - 35 y = 0

What is the solution for (7y^2-t^2)/(y^5)(dy)/(dt)+t/(2y^4)=0 ?
The solution for (7y^2-t^2)/(y^5)(dy)/(dt)+t/(2y^4)=0 is