What is the derivative of y=6^{-4x} ?

The derivative of y=6^{-4x} is -ln(6)*81^{-x}*2^{-4x+2}

What is the first derivative of y=6^{-4x} ?

The first derivative of y=6^{-4x} is -ln(6)*81^{-x}*2^{-4x+2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 6^{- 4 x}

- ln (6) \cdot 8 1^{- x} \cdot 2^{- 4 x + 2}

Solution steps

\frac{d}{d x} (6^{- 4 x})

Simplify

6^{- 4 x} : 129 6^{- x}

= \frac{d}{d x} (129 6^{- x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

129 6^{- x} = e^{(- x) l n (1296)}

= \frac{d}{d x} (e^{(- x) l n (1296)})

Apply the chain rule:

e^{(- x) l n (1296)} \frac{d}{d x} ((- x) ln (1296))

= e^{(- x) l n (1296)} \frac{d}{d x} ((- x) ln (1296))

\frac{d}{d x} ((- x) ln (1296)) = - 4 ln (6)

= e^{(- x) l n (1296)} (- 4 ln (6))

Simplify

e^{(- x) l n (1296)} (- 4 ln (6)) : - ln (6) \cdot 8 1^{- x} \cdot 2^{- 4 x + 2}

= - ln (6) \cdot 8 1^{- x} \cdot 2^{- 4 x + 2}

\frac{d}{d t} (e^{t} t)

\frac{d}{d x} ((2 + 3 x)^{3})

e^{t}

x \to \infty + lim (e^{- x})

\int sin (y) - y sin (x) d x

What is the derivative of y=6^{-4x} ?
The derivative of y=6^{-4x} is -ln(6)*81^{-x}*2^{-4x+2}
What is the first derivative of y=6^{-4x} ?
The first derivative of y=6^{-4x} is -ln(6)*81^{-x}*2^{-4x+2}