What is the derivative of 3x^4-2x^3+1 ?

The derivative of 3x^4-2x^3+1 is 12x^3-6x^2

What is the first derivative of 3x^4-2x^3+1 ?

The first derivative of 3x^4-2x^3+1 is 12x^3-6x^2

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\frac{d}{d x} (3 x^{4} - 2 x^{3} + 1)

12 x^{3} - 6 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 2 x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (1) = 0

= 12 x^{3} - 6 x^{2} + 0

Simplify

= 12 x^{3} - 6 x^{2}

\int 5 csc^{2} (x) d x

\int \frac{x + 2}{2 x ^{2} - x} d x

\int e^{(\frac{x ^{2}}{2})} d x

x \to 7 + lim (3)

\frac{\partial}{\partial x} (e^{x^{2} + y^{2} + 1})

What is the derivative of 3x^4-2x^3+1 ?
The derivative of 3x^4-2x^3+1 is 12x^3-6x^2
What is the first derivative of 3x^4-2x^3+1 ?
The first derivative of 3x^4-2x^3+1 is 12x^3-6x^2