What is the solution for 2xy(dy)/(dx)+x^2-y^2=0 ?

The solution for 2xy(dy)/(dx)+x^2-y^2=0 is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}

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2xy(dy)/(dx)+x^2-y^2=0

2 x y \frac{d y}{d x} + x^{2} - y^{2} = 0

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

Solution steps

2 x y \frac{d y}{d x} + x^{2} - y^{2} = 0

Solve Bernoulli ODE:

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

f (x) = x, (9, 3)

y = \frac{3}{x}, y = 12 x, y = \frac{1}{12} x

y = x (x + 2)

f (x) = \frac{x}{4 + x}

y = ln (8 + ln (x))

What is the solution for 2xy(dy)/(dx)+x^2-y^2=0 ?
The solution for 2xy(dy)/(dx)+x^2-y^2=0 is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}