What is the limit as x approaches 4 of x^2(-16x)/(x-4) ?

The limit as x approaches 4 of x^2(-16x)/(x-4) is diverges

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limit as x approaches 4 of x^2(-16x)/(x-4)

x \to 4 lim (x^{2} \frac{- 16 x}{x - 4})

diverges

Solution steps

x \to 4 lim (x^{2} \frac{- 16 x}{x - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (x^{2} \frac{- 16 x}{x - 4}) = - \infty

x \to 4 - lim (x^{2} \frac{- 16 x}{x - 4}) = \infty

= diverges

\frac{d}{d x} (\frac{e ^{2 x} - 1}{e ^{2 x} + 1})

y^{^{''}} + 14 y^{^{'}} + 100 y = 10 sin (2 π \cdot x) + 5 sin (π \cdot x)

\int \frac{1}{( x ^{2} + 1 ) ^{2} ( x ^{2} - 1 )} d x

3 y^{^{''}} + y^{^{'}} + 2 y = 0

\int \frac{4 x ^{2}}{x ^{3} + 8} d x

What is the limit as x approaches 4 of x^2(-16x)/(x-4) ?
The limit as x approaches 4 of x^2(-16x)/(x-4) is diverges