What is the solution for x^2y^{''}+xy^'-y=0,y(1)=1,y^'(1)=4 ?

The solution for x^2y^{''}+xy^'-y=0,y(1)=1,y^'(1)=4 is y=(1+3/2)x-3/(2x)

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x^2y^{''}+xy^'-y=0,y(1)=1,y^'(1)=4

x^{2} y^{^{''}} + x y^{^{'}} - y = 0, y (1) = 1, y^{^{'}} (1) = 4

y = (1 + \frac{3}{2}) x - \frac{3}{2 x}

Solution steps

x^{2} y^{''} (x) + x y^{'} (x) - y = 0

Solve linear ODE:

y = (1 + \frac{3}{2}) x - \frac{3}{2 x}

y = (1 + \frac{3}{2}) x - \frac{3}{2 x}

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What is the solution for x^2y^{''}+xy^'-y=0,y(1)=1,y^'(1)=4 ?
The solution for x^2y^{''}+xy^'-y=0,y(1)=1,y^'(1)=4 is y=(1+3/2)x-3/(2x)