What is the derivative of 2x-sin(2x) ?

The derivative of 2x-sin(2x) is 2-cos(2x)*2

What is the first derivative of 2x-sin(2x) ?

The first derivative of 2x-sin(2x) is 2-cos(2x)*2

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\frac{d}{d x} (2 x - sin (2 x))

2 - cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 x - sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 2 - cos (2 x) \cdot 2

\frac{d}{d x} (x^{3} - 3 x + 3)

f (x) = \frac{2}{x}, at x = \frac{1}{16}

\int \frac{1}{x \cdot ( ln ( x ) ) ^{p}} d x

\frac{d y}{d x} = - 11

f (x) = 3 x^{2} - x + 5

What is the derivative of 2x-sin(2x) ?
The derivative of 2x-sin(2x) is 2-cos(2x)*2
What is the first derivative of 2x-sin(2x) ?
The first derivative of 2x-sin(2x) is 2-cos(2x)*2