What is the slope ofintercept (-3,5),(-1,-4) ?

The slope ofintercept (-3,5),(-1,-4) is y=-9/2 x-17/2

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slope ofintercept (-3,5),(-1,-4)

slope intercept

(- 3, 5), (- 1, - 4)

y = - \frac{9}{2} x - \frac{17}{2}

Solution steps

Compute the slope

(- 3, 5), (- 1, - 4) : m = - \frac{9}{2}

Compute the

y

intercept:

b = - \frac{17}{2}

Construct the line equation

y = mx + b

where

m = - \frac{9}{2}

and

b = - \frac{17}{2}

y = - \frac{9}{2} x - \frac{17}{2}

\frac{\partial}{\partial u} (\frac{1}{3} (u + v))

\int - sin (3 t) d t

\frac{d}{d x} (ln (2 x^{2}))

\int 9 (x + 7)^{2} ln (x + 7) d x

\int \frac{7 x + 6}{x ^{9}} d x

What is the slope ofintercept (-3,5),(-1,-4) ?
The slope ofintercept (-3,5),(-1,-4) is y=-9/2 x-17/2