What is the integral of 8sin^2(pix)cos^5(pix) ?

The integral of 8sin^2(pix)cos^5(pix) is 8/pi (1/3 sin^3(pix)-2/5 sin^5(pix)+1/7 sin^7(pix))+C

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integral of 8sin^2(pix)cos^5(pix)

\int 8 sin^{2} (π x) cos^{5} (π x) d x

\frac{8}{π} (\frac{1}{3} sin^{3} (π x) - \frac{2}{5} sin^{5} (π x) + \frac{1}{7} sin^{7} (π x)) + C

Solution steps

\int 8 sin^{2} (π x) cos^{5} (π x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int sin^{2} (π x) cos^{5} (π x) d x

Apply u-substitution

: \int sin^{2} (u) cos^{5} (u) \frac{1}{π} d u

= 8 \cdot \int sin^{2} (u) cos^{5} (u) \frac{1}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \frac{1}{π} \cdot \int sin^{2} (u) cos^{5} (u) d u

Rewrite using trig identities

= 8 \cdot \frac{1}{π} \cdot \int (1 - sin^{2} (u))^{2} cos (u) sin^{2} (u) d u

Apply u-substitution

: \int v^{2} (1 - v^{2})^{2} d v

= 8 \cdot \frac{1}{π} \cdot \int v^{2} (1 - v^{2})^{2} d v

Expand

v^{2} (1 - v^{2})^{2} : v^{2} - 2 v^{4} + v^{6}

= 8 \cdot \frac{1}{π} \cdot \int v^{2} - 2 v^{4} + v^{6} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 8 \cdot \frac{1}{π} (\int v^{2} d v - \int 2 v^{4} d v + \int v^{6} d v)

\int v^{2} d v = \frac{v ^{3}}{3}

\int 2 v^{4} d v = \frac{2 v ^{5}}{5}

\int v^{6} d v = \frac{v ^{7}}{7}

= 8 \cdot \frac{1}{π} (\frac{v ^{3}}{3} - \frac{2 v ^{5}}{5} + \frac{v ^{7}}{7})

Substitute back

= 8 \cdot \frac{1}{π} (\frac{sin ^{3} ( π x )}{3} - \frac{2 sin ^{5} ( π x )}{5} + \frac{sin ^{7} ( π x )}{7})

Simplify

8 \cdot \frac{1}{π} (\frac{sin ^{3} ( π x )}{3} - \frac{2 sin ^{5} ( π x )}{5} + \frac{sin ^{7} ( π x )}{7}) : \frac{8}{π} (\frac{1}{3} sin^{3} (π x) - \frac{2}{5} sin^{5} (π x) + \frac{1}{7} sin^{7} (π x))

= \frac{8}{π} (\frac{1}{3} sin^{3} (π x) - \frac{2}{5} sin^{5} (π x) + \frac{1}{7} sin^{7} (π x))

Add a constant to the solution

= \frac{8}{π} (\frac{1}{3} sin^{3} (π x) - \frac{2}{5} sin^{5} (π x) + \frac{1}{7} sin^{7} (π x)) + C

(x^{2} sin (x) + 4 y) d x + (x) d y = 0

\int ln (x + (x^{2} - 1)) d x

ln (sec (x) + tan (x))

\int 1 + 9 sin^{2} (3 x) d x

x \to 0 lim (\frac{( x ^{2} - 4 x )}{x})

What is the integral of 8sin^2(pix)cos^5(pix) ?
The integral of 8sin^2(pix)cos^5(pix) is 8/pi (1/3 sin^3(pix)-2/5 sin^5(pix)+1/7 sin^7(pix))+C