What is the integral of 17arctan(x) ?

The integral of 17arctan(x) is 17(xarctan(x)-1/2 ln|x^2+1|)+C

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integral of 17arctan(x)

\int 17 arctan (x) d x

17 (x arctan (x) - \frac{1}{2} ln x^{2} + 1) + C

Solution steps

\int 17 arctan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 17 \cdot \int arctan (x) d x

Apply Integration By Parts

: x arctan (x) - \int \frac{x}{x ^{2} + 1} d x

= 17 (x arctan (x) - \int \frac{x}{x ^{2} + 1} d x)

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1

= 17 (x arctan (x) - \frac{1}{2} ln x^{2} + 1)

Add a constant to the solution

= 17 (x arctan (x) - \frac{1}{2} ln x^{2} + 1) + C

x \to - 9 + lim (3 x^{2} - 4 x - 7)

\int sin (θ) (cot (θ) + csc (θ)) d θ

\frac{\partial}{\partial x} (6 x + 6 y^{2})

\frac{d}{d x} (x f (x))

(\frac{d y}{d x}) = y + 2 x + 5 - 2

What is the integral of 17arctan(x) ?
The integral of 17arctan(x) is 17(xarctan(x)-1/2 ln|x^2+1|)+C