What is the derivative of 2x*cos(x^2) ?

The derivative of 2x*cos(x^2) is 2(cos(x^2)-2x^2sin(x^2))

What is the first derivative of 2x*cos(x^2) ?

The first derivative of 2x*cos(x^2) is 2(cos(x^2)-2x^2sin(x^2))

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derivative of

2 x \cdot cos (x^{2})

2 (cos (x^{2}) - 2 x^{2} sin (x^{2}))

Solution steps

\frac{d}{d x} (2 x cos (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x cos (x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = cos (x^{2})

= 2 (\frac{d x}{d x} cos (x^{2}) + \frac{d}{d x} (cos (x^{2})) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (cos (x^{2})) = - sin (x^{2}) \cdot 2 x

= 2 (1 \cdot cos (x^{2}) + (- sin (x^{2}) \cdot 2 x) x)

Simplify

2 (1 \cdot cos (x^{2}) + (- sin (x^{2}) \cdot 2 x) x) : 2 (cos (x^{2}) - 2 x^{2} sin (x^{2}))

= 2 (cos (x^{2}) - 2 x^{2} sin (x^{2}))

\int \frac{1}{1 0 ^{x}} d x

\int \frac{x ^{4}}{3355} d x

y^{^{''}} + 2 y^{^{'}} - 3 y = e^{- x}

y = \frac{e ^{x}}{x ^{2}}

\int - sin^{2} (x) cos (x) d x

What is the derivative of 2x*cos(x^2) ?
The derivative of 2x*cos(x^2) is 2(cos(x^2)-2x^2sin(x^2))
What is the first derivative of 2x*cos(x^2) ?
The first derivative of 2x*cos(x^2) is 2(cos(x^2)-2x^2sin(x^2))