What is (\partial)/(\partial y)(7x^2+e^{2y}) ?

The answer to (\partial)/(\partial y)(7x^2+e^{2y}) is 2e^{2y}

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(\partial)/(\partial y)(7x^2+e^{2y})

\frac{\partial}{\partial y} (7 x^{2} + e^{2 y})

2 e^{2 y}

Solution steps

\frac{\partial}{\partial y} (7 x^{2} + e^{2 y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (7 x^{2}) + \frac{\partial}{\partial y} (e^{2 y})

\frac{\partial}{\partial y} (7 x^{2}) = 0

\frac{\partial}{\partial y} (e^{2 y}) = e^{2 y} \cdot 2

= 0 + e^{2 y} \cdot 2

Simplify

= 2 e^{2 y}

\int 4 x (x^{2} + 26000)^{- \frac{2}{3}} d x

f (x) = (x - 4) (3 - x)^{3}

\frac{d}{d x} ((x - 2)^{2} \cdot (x + 4))

\frac{d}{d x} (\frac{2 cos ( x )}{x + 1})

x \to 0 + lim (x)

What is (\partial)/(\partial y)(7x^2+e^{2y}) ?
The answer to (\partial)/(\partial y)(7x^2+e^{2y}) is 2e^{2y}