What is the derivative of-xcos(x+x) ?

The derivative of-xcos(x+x) is -cos(x)+xsin(x)+1

What is the first derivative of-xcos(x+x) ?

The first derivative of-xcos(x+x) is -cos(x)+xsin(x)+1

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\frac{d}{d x} (- x cos (x) + x)

- cos (x) + x sin (x) + 1

Solution steps

\frac{d}{d x} (- x cos (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x cos (x)) + \frac{d x}{d x}

\frac{d}{d x} (x cos (x)) = cos (x) - x sin (x)

\frac{d x}{d x} = 1

= - (cos (x) - x sin (x)) + 1

Simplify

= - cos (x) + x sin (x) + 1

\frac{\partial}{\partial y} (x^{4} + y^{4} + 3 x^{2} y^{3})

\frac{\partial}{\partial x} (x e^{- x^{2}})

\frac{1}{s + 1 ( - 2 s + 10 )}

n = 1 \sum \infty \frac{( - 5 ) ^{n}}{3 ^{2 n + 1}}

\frac{d}{d x} (32 cos (x))

What is the derivative of-xcos(x+x) ?
The derivative of-xcos(x+x) is -cos(x)+xsin(x)+1
What is the first derivative of-xcos(x+x) ?
The first derivative of-xcos(x+x) is -cos(x)+xsin(x)+1