What is the solution for y^{'''}+7y^{''}+10y^'=0 ?

The solution for y^{'''}+7y^{''}+10y^'=0 is y=c_{1}+c_{2}e^{-2t}+c_{3}e^{-5t}

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y^{'''}+7y^{''}+10y^'=0

y^{^{'''}} + 7 y^{^{''}} + 10 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 2 t} + c_{3} e^{- 5 t}

Solution steps

y^{'''} (t) + 7 y^{''} (t) + 10 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 t} + c_{3} e^{- 5 t}

y = c_{1} + c_{2} e^{- 2 t} + c_{3} e^{- 5 t}

(- 4) (0.2)

3 x^{3} - 2 x^{2} - x - 5

y = \frac{4}{5} x + 1

\frac{\partial}{\partial x} (x cos (x y))

f (x) = x^{3} + 1

What is the solution for y^{'''}+7y^{''}+10y^'=0 ?
The solution for y^{'''}+7y^{''}+10y^'=0 is y=c_{1}+c_{2}e^{-2t}+c_{3}e^{-5t}