What is the derivative of 2x+(4x/(3x-1)) ?

The derivative of 2x+(4x/(3x-1)) is 2-4/((3x-1)^2)

What is the first derivative of 2x+(4x/(3x-1)) ?

The first derivative of 2x+(4x/(3x-1)) is 2-4/((3x-1)^2)

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\frac{d}{d x} (2 x + \frac{4 x}{3 x - 1})

2 - \frac{4}{( 3 x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (2 x + \frac{4 x}{3 x - 1})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{4 x}{3 x - 1})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{4 x}{3 x - 1}) = - \frac{4}{( 3 x - 1 ) ^{2}}

= 2 - \frac{4}{( 3 x - 1 ) ^{2}}

f (x) = \frac{4 x}{x ^{2} - 5}, at x = 3

\int \frac{1}{x x ^{2} - 9} d x

\int_{0}^{2} 1

\int (3 x^{5} - 4)^{2} \cdot 5 x^{4} d x

y^{^{''}} + 2 \cdot 2.5 \cdot 4 \cdot y^{^{'}} + 16 y = 0

What is the derivative of 2x+(4x/(3x-1)) ?
The derivative of 2x+(4x/(3x-1)) is 2-4/((3x-1)^2)
What is the first derivative of 2x+(4x/(3x-1)) ?
The first derivative of 2x+(4x/(3x-1)) is 2-4/((3x-1)^2)