What is the integral of (4sec(x)tan(x)-2sec^2(x)) ?

The integral of (4sec(x)tan(x)-2sec^2(x)) is 4sec(x)-2tan(x)+C

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integral of (4sec(x)tan(x)-2sec^2(x))

\int (4 sec (x) tan (x) - 2 sec^{2} (x)) d x

4 sec (x) - 2 tan (x) + C

Solution steps

\int 4 sec (x) tan (x) - 2 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 sec (x) tan (x) d x - \int 2 sec^{2} (x) d x

\int 4 sec (x) tan (x) d x = 4 sec (x)

\int 2 sec^{2} (x) d x = 2 tan (x)

= 4 sec (x) - 2 tan (x)

Add a constant to the solution

= 4 sec (x) - 2 tan (x) + C

\int 10 25 - x d x

x y^{2}

\int_{0}^{\frac{π}{4}} 2 sec^{3} (x) d x

(\frac{u ^{3} - 1}{u ^{3} + 1})^{8}

\frac{\partial}{\partial x} (4 - 2 xx)

What is the integral of (4sec(x)tan(x)-2sec^2(x)) ?
The integral of (4sec(x)tan(x)-2sec^2(x)) is 4sec(x)-2tan(x)+C