What is the limit as x approaches 1+of (-1)/(x^2-1) ?

The limit as x approaches 1+of (-1)/(x^2-1) is -infinity

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limit as x approaches 1+of (-1)/(x^2-1)

x \to 1 + lim (\frac{- 1}{x ^{2} - 1})

- \infty

Solution steps

x \to 1 + lim (\frac{- 1}{x ^{2} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{2} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= - \infty

\int \frac{x}{( x ^{2} + 4 ) ^{2}} d x

- \frac{11}{s ^{4}}

n = 1 \sum \infty \frac{n x ^{n}}{5 ^{n}}

f (x) = \frac{x ^{3} + 5}{x ^{2} + 1}, at x = - 1

\int \frac{3 x - 3}{( x ^{2} - 2 x + 6 ) ^{2}} d x

What is the limit as x approaches 1+of (-1)/(x^2-1) ?
The limit as x approaches 1+of (-1)/(x^2-1) is -infinity