What is the tangent of f(x)=sqrt(x+6),(10,4) ?

The tangent of f(x)=sqrt(x+6),(10,4) is y= 1/8 x+11/4

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tangent of f(x)=sqrt(x+6),(10,4)

tangent of

f (x) = x + 6, (10, 4)

y = \frac{1}{8} x + \frac{11}{4}

Solution steps

Find the slope of

f (x) = x + 6 : \frac{df ( x )}{d x} = \frac{1}{2 x + 6}

Compute the slope of

f (x) = x + 6

(10, 4) : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(10, 4) : y = \frac{1}{8} x + \frac{11}{4}

y = \frac{1}{8} x + \frac{11}{4}

\int \frac{1}{2} (1 - cos (2 x)) d x

\frac{d y}{d x} = x + 5 y

ln (x^{2} + y^{2})

\int \frac{( 2 - x ^{2} )}{x ^{3} + 3 x ^{2} + 2 x} d x

x \to + 4 lim (3 e^{1.7 x} + 1)

What is the tangent of f(x)=sqrt(x+6),(10,4) ?
The tangent of f(x)=sqrt(x+6),(10,4) is y= 1/8 x+11/4