What is the tangent of y= 2/(x-4),(6,1) ?

The tangent of y= 2/(x-4),(6,1) is y=-1/2 x+4

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tangent of y= 2/(x-4),(6,1)

tangent of

y = \frac{2}{x - 4}, (6, 1)

y = - \frac{1}{2} x + 4

Solution steps

Find the slope of

y = \frac{2}{x - 4} : \frac{d y}{d x} = - \frac{2}{( x - 4 ) ^{2}}

Compute the slope of

y = \frac{2}{x - 4}

(6, 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(6, 1) : y = - \frac{1}{2} x + 4

y = - \frac{1}{2} x + 4

\frac{d y}{d x} = x^{3} (1 - y)

\frac{d}{d x} (\frac{2 x ^{2}}{x - 2})

\frac{\partial}{\partial x} (ln (\frac{y ^{6}}{x ^{10}}))

\int 4 x^{2} e^{2 x} d x

\int 8 x e^{5 x} d x

What is the tangent of y= 2/(x-4),(6,1) ?
The tangent of y= 2/(x-4),(6,1) is y=-1/2 x+4