What is the tangent of y=(sqrt(x))/(x+2),(4, 2/6) ?

The tangent of y=(sqrt(x))/(x+2),(4, 2/6) is y=-1/72 x+7/18

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tangent of y=(sqrt(x))/(x+2),(4, 2/6)

tangent of

y = \frac{x}{x + 2}, (4, \frac{2}{6})

y = - \frac{1}{72} x + \frac{7}{18}

Solution steps

Find the slope of

y = \frac{x}{x + 2} : \frac{d y}{d x} = \frac{- x + 2}{2 x ( x + 2 ) ^{2}}

Compute the slope of

y = \frac{x}{x + 2}

(4, \frac{2}{6}) : m = - \frac{1}{72}

Find the line with slope m=

- \frac{1}{72}

and passing through

(4, \frac{2}{6}) : y = - \frac{1}{72} x + \frac{7}{18}

y = - \frac{1}{72} x + \frac{7}{18}

- 2 x^{5} + 3 x^{2} - 7

\frac{\partial}{\partial x} (4 - 2 y + 4 x y)

\int (x + \frac{1}{x}) d x

\frac{d ^{2}}{d x ^{2}} (\frac{3 x - 2}{2 x + 5})

θ \to 0 lim (\frac{sin ( θ )}{θ})

What is the tangent of y=(sqrt(x))/(x+2),(4, 2/6) ?
The tangent of y=(sqrt(x))/(x+2),(4, 2/6) is y=-1/72 x+7/18