What is the derivative of e^{-3x}+e^{4x} ?

The derivative of e^{-3x}+e^{4x} is -3e^{-3x}+e^{4x}*4

What is the first derivative of e^{-3x}+e^{4x} ?

The first derivative of e^{-3x}+e^{4x} is -3e^{-3x}+e^{4x}*4

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derivative of

e^{- 3 x} + e^{4 x}

- 3 e^{- 3 x} + e^{4 x} \cdot 4

Solution steps

\frac{d}{d x} (e^{- 3 x} + e^{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- 3 x}) + \frac{d}{d x} (e^{4 x})

\frac{d}{d x} (e^{- 3 x}) = - 3 e^{- 3 x}

\frac{d}{d x} (e^{4 x}) = e^{4 x} \cdot 4

= - 3 e^{- 3 x} + e^{4 x} \cdot 4

x \to 2 lim (2 x^{2} + 6)

x \to 0 + lim (ln (\frac{2}{x ^{2}}))

\int_{0}^{\frac{π}{2}} 4 sin^{2} (3 x) d x

\frac{3}{x ( x + 1 ) ^{2}}

\int \frac{( 8 x ^{3} + 3 )}{( x ^{2} + 2 ) ^{2}} d x

What is the derivative of e^{-3x}+e^{4x} ?
The derivative of e^{-3x}+e^{4x} is -3e^{-3x}+e^{4x}*4
What is the first derivative of e^{-3x}+e^{4x} ?
The first derivative of e^{-3x}+e^{4x} is -3e^{-3x}+e^{4x}*4